LogFAQs > #369089

LurkerFAQs ( 06.29.2011-09.11.2012 ), Active DB, DB1, DB2, DB3, DB4, DB5, DB6, DB7, DB8, DB9, DB10, DB11, DB12, Clear
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Topicquick calc question that I'm drawing a blank on
Ness26
09/22/11 3:10:00 PM
#11:


f(x) = | x + 1|

Define f(x) piecewise.

For x < -1, f(x) = -x - 1
For x >= -1, f(x) = x + 1

Take derivatives.

For x < -1, f(x) = -1
For x > -1, f(x) = 1

Derivative is positive for x > -1

The function isn't differentiable at x = -1 so you can't really say it is increasing or decreasing there.

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