f(x) = 5 / (5x^2 - 8)
so i set the bottom part = 0
i got x = (2 radical 10) / 5
How do I express this in interval notation? Isn't it just x doesn't equal (2 radical 10) / 5?
--
KA POWIE
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| Topic | How do you find the domain of this function? |
| TheFlyingWolfen 09/22/11 5:52:00 PM #1: |
f(x) = 5 / (5x^2 - 8)
so i set the bottom part = 0 i got x = (2 radical 10) / 5 How do I express this in interval notation? Isn't it just x doesn't equal (2 radical 10) / 5? -- KA POWIE ... Copied to Clipboard! |
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