LogFAQs > #905501869

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2SweetforTurtle
07/21/18 11:43:03 PM
#78:


MelzezDoor posted...
2SweetforTurtle posted...
Youre ignoring the fact that it states youre choosing from the SAME box. The total number of gold balls is irrelevant. Once you choose a box, theres a 50 percent chance that youll get a gold ball (three gold and three silver balls). Picking a gold ball out of the box that you chose eliminates the box that has zero gold balls from the equation.

Exactly. You had to have chosen the right box first so that probability cannot be ignored. The 1/3 it takes will take priority and therefore change the outcome of the last gold ball so 16 2/3% total.


Im not entirely sure what you mean by taking priority.

Are you basically saying the math of this is 1/3 divided by 1/2? Which in turn is solved by multiplying by the reciprocal, leaving you with 1/3x2/1. Therefore 2/3?

1/3 = possibility of picking the box with no gold balls
1/2 = possibility of drawing a gold ball
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