LogFAQs > #913945796

LurkerFAQs, Active DB, DB1, DB2, DB3, Database 4 ( 07.23.2018-12.31.2018 ), DB5, DB6, DB7, DB8, DB9, DB10, DB11, DB12, Clear

Topic List	Page List: 1
Topic	6÷2(1+2)=?
Sariana21 12/11/18 12:43:50 PM #15:	Umbreon posted... If I'm not mistaken.... 62(1+2) 62(3) 66 =1 You're mistaken, but you shouldn't be. The rule is stupid. But technically the rule is that multiplication and division have equal status and you go left to right, so it is solved by adding the 1 and 2 first (because parentheses come first), then dividing 6 by 2, then multiplying by the 3. But what you wrote SHOULD be the rule. It makes much more sense. --- ___ Sari, Mom to DS (07/04) and DD (01/08) <cite>Sariana21 posted [p:913945796] in 6÷2... [t:77292057]...</cite> <quote><cite>Umbreon posted...</cite> <quote>If I'm not mistaken.... 62(1+2) 62(3) 66 =1</quote> You're mistaken, but you shouldn't be. The rule is stupid. But technically the rule is that multiplication and division have equal status and you go left to right, so it is solved by adding the 1 and 2 first (because parentheses come first), then dividing 6 by 2, then multiplying by the 3. But what you wrote SHOULD be the rule. It makes much more sense. --- ___ Sari, Mom to DS (07/04) and DD (01/08)</quote> ... Copied to Clipboard!
Topic List	Page List: 1