LogFAQs > #938642307

The probability a single person does not have a pair is (24C4*2^4)/48C4 = 10626*16/194580 = 87.38%.

That agrees with xp's rendition.

As for the "at least one person" version, it's slightly more complicated than the way xp put it because as you take cards from the deck without replacement, it narrows the options a bit for the others, but I would presume that his calculation is accurate enough for most purposes.

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VGMC13 champion: Ar Nosurge - Class::EXSPHERE_NOSURGE;