LogFAQs > #949531118

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TopicMIT Applicants were asked to solve this VERY DIFFICULT MATH QUESTION..Can you???
Sahuagin
01/15/21 12:38:10 PM
#8:


3(x - 2) = (y - 2)
3x - 6 = y - 2
3x - y - 4 = 0

2(x + 14) = (y + 14)
2x + 28 = y + 14
2x - y + 14 = 0

3x - y - 4 = 0
2x - y + 14 = 0
===================
x - 18 = 0
x = 18

2(18) - y + 14 = 0
36 + 14 = y
y = 50


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