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TopicA clever math question for you 140+ IQ guys out there.
Questionmarktarius
06/03/23 12:37:47 AM
#18:


You just need two cubes where the difference is a power of two.
The easiest solution would be a cube that's one greater than any given power of two. Given that numbers are infinite, there's probably a collision somewhere.

X^3 = 2^Z + 1
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