LogFAQs > #411092

LurkerFAQs ( 06.29.2011-09.11.2012 ), Active DB, DB1, DB2, DB3, DB4, DB5, DB6, DB7, DB8, DB9, DB10, DB11, DB12, Clear
Topic List
Page List: 1
Topichow to solve this trig/calc problem?
foolm0ron
10/02/11 9:50:00 PM
#20:


From: HeroicLinusReed | #014
log (base 8) 2 + log (base 4) 2 = ?


For this, you just need to figure out the exact value of each. If you can't use a calculator, you should hope that the values are clean (like they are in this case)

log (base 8) 2 = x
8^x = 2
2^(3x) = 2^(1)
3x = 1
x = 1/3
log (base 8) 2 = 1/3

similarly you can find log (base 4) 2 = 1/2

--
_foolmo_
'To be foolmo'd is to be better opinion'd.' - Blairville
... Copied to Clipboard!
Topic List
Page List: 1