Board 8 > In Computer Science, is xor the solution to every problem?

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ShockKirby80
12/20/11 2:53:00 PM
#1:


Yes xor no?

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_Regaro_
12/20/11 2:54:00 PM
#2:


If only

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SpeedYoshi
12/20/11 2:57:00 PM
#3:


if you want it to be!

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paperwarior
12/20/11 2:59:00 PM
#4:


If only

Were you going for an iff joke there?

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_Regaro_
12/20/11 3:00:00 PM
#5:


From: paperwarior | #004
If only

Were you going for an iff joke there?


if(only)
print "xor is the solution to every problem"

<_<

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Ness26
12/20/11 3:00:00 PM
#6:


I'm not sure about that, but I know the solution to every CS interview question is a hash map.

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foolm0ron
12/20/11 3:04:00 PM
#7:


From: Ness26 | #006
I'm not sure about that, but I know the solution to every CS interview question is a hash map.


That's not true, what about "how do you initialize an array in constant time?"

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_Regaro_
12/20/11 3:06:00 PM
#8:


From: foolm0ron | #007
That's not true, what about "how do you initialize an array in constant time?"


By using a linked hash map obviously

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The Mana Sword
12/20/11 3:06:00 PM
#9:


O(log(n))

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insanity domain
12/20/11 3:09:00 PM
#10:


^This

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foolm0ron
12/20/11 3:09:00 PM
#11:


From: _Regaro_ | #008
By using a linked hash map obviously


Wait damn that's actually the solution...
Okay how about......... uh... this is pretty hard

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ShockKirby80
12/20/11 3:31:00 PM
#12:


The Mana Sword posted...
O(log(n))

O(2^n)

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_Regaro_
12/20/11 3:43:00 PM
#13:


From: ShockKirby80 | #012
The Mana Sword posted...
O(log(n))

O(2^n)


O(n^n) tbqh


does such a function even exist <_< A loop of recursive calls would do it right

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BlAcK TuRtLe
12/20/11 3:44:00 PM
#14:


Technically, NAND is the solution to every problem, since you can make any circuit using NAND

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foolm0ron
12/20/11 3:49:00 PM
#15:


From: _Regaro_ | #013
O(n^n) tbqh


does such a function even exist <_< A loop of recursive calls would do it right


google says depth-first search on n branches, n levels deep

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ShockKirby80
12/20/11 3:52:00 PM
#16:


_Regaro_ posted...
From: ShockKirby80 | #012
The Mana Sword posted...
O(log(n))

O(2^n)
O(n^n) tbqh


does such a function even exist <_< A loop of recursive calls would do it right


On a CS test I had, someone put O(n!!) when the answer was O(n!). The teacher was amused.

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