Current Events > I never imagined 802.1x would be so difficult to implement

(+) Yeah! (+)

As a part of improving the security of the organization, network security is a huge deal. I'm essentially gonna have to roll this out department by department, and probably user by user.

Gonna be fun when I get around to the executives' computers...
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One of the hiring managers here tunes out every time someone comes in and says "Well at my home..." as a response to being asked about wireless networking.

It's like a guaranteed way to not get hired.
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ChromaticAngel posted...

One of the hiring managers here tunes out every time someone comes in and says "Well at my home..." as a response to being asked about wireless networking.

It's like a guaranteed way to not get hired.

LOL, yeah, I remember trying that in an interview a long time ago. I had done ISP tech support for about a year at that time. I didn't get the job.

I had no idea networking was so deep back then.
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Because lack of experience implies lack of skill?
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CableZL posted...

ChromaticAngel posted...

One of the hiring managers here tunes out every time someone comes in and says "Well at my home..." as a response to being asked about wireless networking.

It's like a guaranteed way to not get hired.

LOL, yeah, I remember trying that in an interview a long time ago. I had done ISP tech support for about a year at that time. I didn't get the job.

I had no idea networking was so deep back then.

most recent applicant who did this was also asked "How many IPs are available in a class C IP Address?"

He sat in silence thinking about it really hard for like 5 minutes until the manager said "Just give me your best guess." and he responds "about 150"
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I went to college for 2 years for networking

Then I saw how much was involved

Holy shit

Noped the fuck out
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According to Wikipedia:

Windows defaults to not responding to 802.1X authentication requests for 20 minutes after a failed authentication.

who the fuck thought that was a sane default

wackyteen posted...

I went to college for 2 years for networking

Then I saw how much was involved

Holy shit

Noped the fuck out

networking for small offices isn't really that hard.

shit only gets crazy when you've got a huge office + remote locations and it's got to integrate with your active directory and there is also a vpn and the vpn also has to integrate with active directory etc etc etc.
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ChromaticAngel posted...

most recent applicant who did this was also asked "How many IPs are available in a class C IP Address?"

He sat in silence thinking about it really hard for like 5 minutes until the manager said "Just give me your best guess." and he responds "about 150"

lol

The question is poorly phrased, but yeah... I also bombed a subnetting question when I was about 3 years into doing tech support and tried to interview for a networking job.
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treewojima posted...

According to Wikipedia:

Windows defaults to not responding to 802.1X authentication requests for 20 minutes after a failed authentication.

who the fuck thought that was a sane default

I don't think that's the case any more. I've been testing it out for quite a while, and it's a few seconds at most on my machine.
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CableZL posted...

ChromaticAngel posted...

most recent applicant who did this was also asked "How many IPs are available in a class C IP Address?"

He sat in silence thinking about it really hard for like 5 minutes until the manager said "Just give me your best guess." and he responds "about 150"

lol

The question is poorly phrased, but yeah... I also bombed a subnetting question when I was about 3 years into doing tech support and tried to interview for a networking job.

I actually did bring up that the question could have multiple answers and he said he knows and he'd take anything over 200 and less than 256.

Although according to him the only correct answer is 254 because .0 is network and .255 is broadcast.
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ChromaticAngel posted...

I actually did bring up that the question could have multiple answers and he said he knows and he'd take anything over 200 and less than 256.

Although according to him the only correct answer is 254 because .0 is network and .255 is broadcast.

Yeah, a better way to ask it would be "How many IP addresses are available in a /24 subnet," instead of "How many IP addresses are available in a class C IP address."

You can have a class C subnet that's smaller than a /24, and a class C IP address would just be 1 IP address.

Also, the full class C private range is 192.168.0.0/16, which is (255^2)-2 usable IP addresses.
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Asherlee10 posted...

I wish I knew more network engineering shit.

Same.
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CableZL posted...

ChromaticAngel posted...

I actually did bring up that the question could have multiple answers and he said he knows and he'd take anything over 200 and less than 256.

Although according to him the only correct answer is 254 because .0 is network and .255 is broadcast.

Yeah, a better way to ask it would be "How many IP addresses are available in a /24 subnet," instead of "How many IP addresses are available in a class C IP address."

You can have a class C subnet that's smaller than a /24, and a class C IP address would just be 1 IP address.

Yeah, but that's you intentionally subnetting less than what's available.

and even if you were going to interpret that as subnets, 150 is still nowhere near the right answer. the next biggest block under 256 is 128.

Regardless, the dude also listed himself as an "Expert in DNS" and then couldn't tell us what an AX record was. He clearly just had no fucking idea what he was doing.
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CableZL posted...

Also, the full class C private range is 192.168.0.0/16, which is (255^2)-2 usable IP addresses.

that's all class C addresses. each individual class c only supports 254.
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ChromaticAngel posted...

Yeah, but that's you intentionally subnetting less than what's available.

and even if you were going to interpret that as subnets, 150 is still nowhere near the right answer. the next biggest block under 256 is 128.

Regardless, the dude also listed himself as an "Expert in DNS" and then couldn't tell us what an AX record was. He clearly just had no f***ing idea what he was doing.

Well, if you're talking about a /24 class C subnet, you're already subnetting less than what's available in the full class C range (192.168.0.0/16).

And yeah, 150 definitely wrong.

I also need to learn more about DNS. I don't really get that stuff too much outside of how it works from a basic networking perspective.
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ChromaticAngel posted...

that's all class C addresses. each individual class c only supports 254.

The class for IP addresses refers to the entire range, though. Class A is 10.0.0.0/8, Class B is 172.16.0.0/12, and Class C is 192.168.0.0/16.

A class C subnet would be 254 IP addresses, but a class C IP address is anything from 192.168.0.0 - 192.168.255.255. Usables obviously in between that range.
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At the end of the day, we're both on the same page and I'm just arguing semantics. I know what he means, damn it.

*sits down*
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CableZL posted...

ChromaticAngel posted...

that's all class C addresses. each individual class c only supports 254.

The class for IP addresses refers to the entire range, though. Class A is 10.0.0.0/8, Class B is 172.16.0.0/12, and Class C is 192.168.0.0/16.

A class C subnet would be 254 IP addresses, but a class C IP address is anything from 192.168.0.0 - 192.168.255.255. Usables obviously in between that range.

I suppose if you wanted to read into the question from an extremely technical definition, yes--but you could take it a step farther, as the 192.168/16 is merely private class C IP addresses

"How many IP addresses are available in a Class C IP address" is something I'd probably need a calculator to figure out if we were to count the public ones as well
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Any way... Yeah, doing networking for a company is way more complex than home networking. I wish I had known this years ago.

My job has 6 WAN providers, 4 of them with public internet access.

2 public internet providerrs
2 data MPLS providers with public internet egresses at the data centers
2 voice MPLS providers

My strength at this point is in routing and switching, so it's pretty easy for me to put it all together even though it's very complex. I'm the only guy in the organization that understands networking at whatever level I'm currently at, though.
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I don't do any networking at my job but we've got 2 AD Domains, 1 main data center, 1 DR data center, 1 azure cloud instance, 1 aws instance, one small office closet serverroom, 2 different wireless networks, every employee has phones that have to integrate with all of this + be secure and that's just the stuff that I interact with daily.

there are also a few boxes that we've got in the dc but aren't part of our domains because they're encapsulated and all this shit all has to work with each other at all times.

I'm really thankful sometimes that all I have to do is write code and fix the applications when they break.
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ChromaticAngel posted...

CableZL posted...

ChromaticAngel posted...

that's all class C addresses. each individual class c only supports 254.

The class for IP addresses refers to the entire range, though. Class A is 10.0.0.0/8, Class B is 172.16.0.0/12, and Class C is 192.168.0.0/16.

A class C subnet would be 254 IP addresses, but a class C IP address is anything from 192.168.0.0 - 192.168.255.255. Usables obviously in between that range.

I suppose if you wanted to read into the question from an extremely technical definition, yes--but you could take it a step farther, as the 192.168/16 is merely private class C IP addresses

"How many IP addresses are available in a Class C IP address" is something I'd probably need a calculator to figure out if we were to count the public ones as well

Truth

Truth
192.0.0.0 - 223.255.255.255

Increment is 32, so it's a /4. (192.0.0.0/4)

11110000.00000000.00000000.00000000

So I think it'd be 255^28 IP addresses total or 24161564501550368558430041444810830996032029256261885166168212890625

I think

Edit: no, that's not it... it wouldn't be 255^28. It'd be somewhere between 255^3 and 255^4. About half way in between those, actually.

I think.
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CableZL posted...

It'd be somewhere between 255^3 and 255^4.

It's (255^3 * 31) - (some small number for network and broadcast ips)
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