Current Events > How does a 40psf floor requirement support humans?

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So if you design a floor to 40 pounds per square foot, and assume your two feet have a total square footage of 1, wouldn't that mean wherever you're standing, you are exhibiting a pressure of [your weight] per square foot...? And adults weigh a helluva lot more than 40 pounds...

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Irony posted...

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If it's so easy, please do explain.

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This never made too much sense for me... Like if you have a lifted cadenza weighing 200lbs with six legs, each of those legs will be no more than 0.1sqft, resulting in a pressure of 333psf each.

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Your weight gets distributed by the flooring across a much larger area than the size of your feet.

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uwnim posted...

Your weight gets distributed by the flooring across a much larger area than the size of your feet.

You mean each other floor joist and whatever flooring you have reinforces each other? So what happens if you have like 15 people in a 30sqft area, waiting around (like a waiting room or what not)? That would surely be more than the 40psf overall (say an average of 150lbs per person = 75psf, but the floor is designed only for 40psf).

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