Current Events > Need help with a Calc 1 delta/epsilon problem.

(+) Yeah! (+)

My friend gave me this problem, but can't figure out why he's wrong.

For the limit:
lim(x->2)(x^3-5x+3)=1
illustrate the definition by finding the largest possible values of delta that correspond to epsilon=0.2. Round to four decimal places.

I solved it graphically and got delta=.0279.
Solved it algebraically and got delta=0.2/(x^2+2x-1)=0.2/7

Doing the work:
0<|x-2|<delta
|x^3-5x+3-1|<0.2
|(x-2)(x^2+2x-1)|<0.2
|x-2|<0.2/|(x^2+2x-1)|
|x-2|<delta<0.2/|(x^2+2x-1)|

Plugging x=2+2/7 into f(x) gives ~1.2049, which is larger than epsilon and the incorrect answer. What went wrong?
Hopefully I didn't make any typos here.